Latihan Soal Penyimpanan Sekunder

Soal!

Diketahui :
  • Seek time (s) = 10 ms
  • Kecepatan putar harddsik = 3000 rpm
  • Transfer rate (t) = 1024 byte/s
  • Ukuran blok (B) = 2048 byte
  • Ukuran record (R) = 128 byte
  • Ukuran gap (G) = 64 byte
  • Ukuran pointer (P) = 10
Cari r, Bfr, TR, Btt, W dan t'! (Menggunakan metode fixed blocking, spanned blocking dan unspanned blocking!)

Jawaban :
  1. r = 1/2 * ((60 * 1000)/RPM)
    r = 1/2 * ((60 * 1000)/3000)
    r = 10 s

  2. Bfr
    • Fixed Blocking
      • Bfr = B/R
      Bfr = 2048/128
      Bfr = 16

    • Spanned Blocking
      • Bfr = (B - P) / (R + P)
      Bfr = (2048 - 10) / (128 + 10)
      Bfr = 14,76

    • Unspanned Blocking
      • Bfr = (B - 1 / 2R)/(R + P)
      Bfr = (2048 - 1 / 2128)/(128 + 10)
      Bfr = 14,37

  3. TR = R/t
    TR = 128/1024
    TR = 0,125

  4. Btt = B/t
    Btt = 2048/1024
    Btt = 2

  5. W
    • Fixed Blocking
      • WG = G / Bfr
      WG = 64 / 16
      WG = 4

      WR = B / Bfr
      WR = 2048 / 16
      WR = 128

      W = WG + WR
      W = 4 + 128
      W = 132

    • Spanned Blocking
      • W = P + (P + G) / Bfr
      W = 10 + (10 + 64) / 14,76
      W = 15,01

    • Unspanned Blocking
      • W = P + (1/2R + G) / Bfr
      W = 10 + (1/2128 + 64) / 14,37
      W = 18,9

  6. t'
    • Fixed Blocking
      • t' = (t/2) * {R / (R + W)}
      t' = (1024/2) * {128 / (128 + 132)}
      t' = 250,88

    • Spanned Blocking
      • t' = (t/2) * {R / (R + W)}
      t' = (1024/2) * {128 / (128 + 15,01)}
      t' = 455,68

    • Unspanned Blocking
      • t' = (t/2) * {R / (R + W)}
      t' = (1024/2) * {128 / (128 + 18,9)}
      t' = 445,44

Baca Post Lain :

Penyimpanan Sekunder
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